40x^2+117x-360=0

Solution for 40x^2+117x-360=0 equation:

40x^2+117x-360=0

a = 40; b = 117; c = -360;
Δ = b2-4ac
Δ = 1172-4·40·(-360)
Δ = 71289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{71289}=267$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(117)-267}{2*40}=\frac{-384}{80}
=-4+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(117)+267}{2*40}=\frac{150}{80}
=1+7/8
$